Java OOP GUIDE / WORK ROUNDTABLE CLASS SOLUTIONS TASK – PART 1 – ROUNDTABLE CLASS Here is my solution: public class RoundTable { public double diameter; public double height; public String material; public RoundTable(double td, double th, String tm) { diameter = td; height = th; material = tm; } public String toString() { return "RoundTable:Diameter="+diameter+" Height="+height+" Material="+material; } public int seatingSpots() { if (diameter >= 10) return 15; else if (diameter >= 9) return 14; else if (diameter >= 8) return 12; else if (diameter >= 7) return 11; else if (diameter >= 6) return 9; else if (diameter >= 5) return 8; else if (diameter >= 4) return 6; else if (diameter >= 3) return 3; else //not in chart return 1; } } Note: The implementation of the seatingSpot() method could be different. The coder could have assumed that the exact diameters would be provided. In my implementation, there are issues. If a table would have a diameter of 20, it still would only have 15 seating spots. Also, I give 1 seating spot to tables under 3 diameter TASK – PART 2 – TESTING YOUR ROUNDTABLE CLASS Here is my solution: public class RoundTableTester { public static void main(String[] args) { RoundTable rt = new RoundTable(4.1, 3.0, "wood"); System.out.println(rt); System.out.println(rt.seatingSpots()); } } TASK – PART 3 – SHORT ANSWER QUESTION Here is the statement: int totalSeating = t1.seatingSpots() + t2.seatingSpots() + t3.seatingSpots() + t4.seatingSpots();